A beam of electrons moving at a speed of 106 m-s along a line produces a current of 1-6 - 10-6A- The number of electrons in the 1 metre of the beam is

I=q/t = q/(x/v) = qv/x = nev/x⇒ n = ix/ev = 1.6 × 10^ 6× 1/1.6 × 10^ 19× 10^6 = 10^7 ...

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Standard XI

Physics

The Flow of Electrons as Electric Current

A beam of ele...

Question

A beam of electrons moving at a speed of $10^{6}$ m/s along a line produces a current of $1.6 \times 10^{- 6} A$ . The number of electrons in the 1 metre of the beam is

10^{6}

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10^{7}

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10^{13}

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10^{19}

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Solution

The correct option is B $10^{7}$
$i = \frac{q}{t} = \frac{q}{(\frac{x}{v})} = \frac{q v}{x} = \frac{n e v}{x} \Rightarrow n = \frac{i x}{e v} = \frac{1.6 \times 10^{- 6} \times 1}{1.6 \times 10^{- 19} \times 10^{6}} = 10^{7}$

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A beam of electrons moving at a speed of 106 m/s along a line produces a current of 1.6×10−6A. The number of electrons in the 1 metre of the beam is

The correct option is B 107i=qt=q(xv)=qvx=nevx⇒n=ixev=1.6×10−6×11.6×10−19×106=107

A beam of electrons moving at a speed of $10^{6}$ m/s along a line produces a current of $1.6 \times 10^{- 6} A$ . The number of electrons in the 1 metre of the beam is

The correct option is B $10^{7}$
$i = \frac{q}{t} = \frac{q}{(\frac{x}{v})} = \frac{q v}{x} = \frac{n e v}{x} \Rightarrow n = \frac{i x}{e v} = \frac{1.6 \times 10^{- 6} \times 1}{1.6 \times 10^{- 19} \times 10^{6}} = 10^{7}$