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Question

A beam of light consisting of wavelength 6000˚A and 4500˚A is used in a YDSE with D = 1m and d = 1mm. Find the least distance from central maxima, where bright fringes due to the two wavelengths coincide:

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Solution

Suppose they melt at mth fringe of 1st and nth fringe of 2nd
mβ1=nβ2
m×λ1Dd=n×λ2Dd
m×6000=n×4500
m = 3 and n = 4 for minimum distance
Minimum distance from
Central fridge = mβ1=3×6000×10101×103=1.8mm

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