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Question

A beam of light from a source L is incident normally on a plane mirror fixed at a certain distance x from the source. The beam is reflected back as a spot on a scale placed just above the source L. When the mirror is rotated through a small angle θ, the spot of the light is found to move through a distance y on the scale. The angle θ is given by

A
xy
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B
y2x
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C
yx
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D
x2y
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Solution

The correct option is B y2x
When mirror is rotated by θ angle reflected ray will be rotated by 2θ (because of law of reflection).

yx=tan2θ
Taking small angle approximation
θ=y2x

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