Question

A beam of light is falling on a glass plate at an angle ${60}^{\circ }$. It is found that the reflected light is completely polarized. The angle of refraction when angle of incidence is ${45}^{\circ }$ is

• A. $si{n}^{-1}\left(\frac{\sqrt{3}}{2}\right)$
  
  
• B. $si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$
• C. $si{n}^{-1}\left(\frac{1}{3}\right)$
• D. $si{n}^{-1}\left(\frac{1}{\sqrt{3}}\right)$

Answer 1

The correct option is B $si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$

$\mu =tan{i}_p=tan{60}^{\circ }$
$\mu =\sqrt{3}$
$\mu =\frac{sini}{sinr}=\frac{sin45}{sinr}=\sqrt{3}$
$sinr=\frac{1}{\sqrt{2}\sqrt{3}}=\frac{1}{\sqrt{6}}$
$=si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$