Question

A beam of light is incident on a glass plate at an angle of incidence ${60}^{\circ }$. The reflected ray is polarized. The angle of refraction when the angle of incidence is ${45}^{\circ }$ is

• A. $si{n}^{-1}\left(\frac{\sqrt{3}}{2}\right)$
• B. $co{s}^{-1}\left(\frac{\sqrt{3}}{2}\right)$
• C. $si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$
• D. $si{n}^{-1}\left(\frac{1}{\sqrt{3}}\right)$

Answer 1

The correct option is C $si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$

$\mu =tan{60}^{\circ }=\sqrt{3}$
$\frac{sini}{sinr}=\sqrt{3}\Rightarrow sinr=\frac{sin{45}^{\circ }}{\sqrt{3}}=\frac{1}{\sqrt{6}}$
$\Rightarrow r=si{n}^{-1}\left(\frac{1}{\sqrt{6}}\right)$