wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A beam of light is strikes on a piece of metal whose work function is 6.0 eV. Calculate the maximum kinetic energy of photoelectrons ejected from the metals surface if frequency of light is 7.2×1015Hz.

A
7 eV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
13 eV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
19 eV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
24 eV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
No photoelectrons will be produced
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 24 eV
Given : ν=7.2×1015 Hz ϕ=6.0 eV
Planck's constant h=6.63×10341.6×1019=4.14×1015 eV s
Maximum kinetic energy of photoelectrons K.Emax=hνϕ
K.Emax=(4.14×1015)×(7.2×1015)6.0=306=24 eV

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stopping Potential
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon