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Standard XII

Physics

Stopping Potential

A beam of lig...

Question

A beam of light is strikes on a piece of metal whose work function is 6.0 eV. Calculate the maximum kinetic energy of photoelectrons ejected from the metals surface if frequency of light is $7.2 \times 10^{15} H z$ .

7 eV

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13 eV

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19 eV

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24 eV

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No photoelectrons will be produced

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Solution

The correct option is A 24 eV
Given : $ν = 7.2 \times 10^{15}$ Hz $ϕ = 6.0$ eV
Planck's constant $h = \frac{6.63 \times 10^{- 34}}{1.6 \times 10^{- 19}} = 4.14 \times 10^{- 15}$ eV s
Maximum kinetic energy of photoelectrons $K . E_{m a x} = h ν - ϕ$
$∴$ $K . E_{m a x} = (4.14 \times 10^{- 15}) \times (7.2 \times 10^{15}) - 6.0 = 30 - 6 = 24$ eV

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A beam of light is strikes on a piece of metal whose work function is 6.0 eV. Calculate the maximum kinetic energy of photoelectrons ejected from the metals surface if frequency of light is 7.2×1015Hz.

The correct option is A 24 eVGiven : ν=7.2×1015 Hz ϕ=6.0 eVPlanck's constant h=6.63×10−341.6×10−19=4.14×10−15 eV sMaximum kinetic energy of photoelectrons K.Emax=hν−ϕ∴ K.Emax=(4.14×10−15)×(7.2×1015)−6.0=30−6=24 eV

A beam of light is strikes on a piece of metal whose work function is 6.0 eV. Calculate the maximum kinetic energy of photoelectrons ejected from the metals surface if frequency of light is $7.2 \times 10^{15} H z$ .