1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A beam of light of wavelength 500 nm from a distant source falls on a single slit 2 mm wide and the resulting diffraction pattern is observed on a screen 2.2 m away. The distance between the first dark fringes on either side of the central bright fringe is

A
1.1 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.2 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.4 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.1 mm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 1.1 mmThe distance between the first dark fringes on either side of central maximum is equal to the width of central maximum W=2λDa Where a→Width of slit=2 mm λ→Wavelength of light=500 nm D→distance of screen from slit=2.2 m ⇒W=2×500×10−9×2.22×10−3 m ⇒W=1.1 mm Hence, option (D) is correct. Why this question? Asked in IIT -JEE 1994.

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Light spectrum Tackle
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program