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Byju's Answer
Standard XII
Physics
Wave Equation
A beam of pro...
Question
A beam of proton moving with velocity 4 ×10^5m\s enters in a uniform magnetic field of 0.3 T a5 an angle of 60° to the magnetic field . calculate radius of helical path and pitch of helix
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Similar questions
Q.
A beam of protons with a velocity of
4
×
10
5
m
/
s
enters in a region of uniform magnetic field of 0.3 T. The velocity makes an angle of
60
0
with the magnetic field. Find the radius of the helical path taken by the proton beam and the pitch of the helix
Q.
A beam of protons with a velocity
4.0
×
10
5
m
s
−
1
enters a uniform magnetic field of 0.3 T at an angle of
60
o
to the magnetic field. If the radius of the helical path taken by the proton beam is
1.2
×
10
−
X
m
. Find X?
Q.
A beam of protons with speed
4
×
10
5
ms
–
1
enters a uniform magnetic field of
0.3
T
at an angle of
60
∘
to the magnetic field. The pitch of the resulting helical path of protons is close to :
(
Mass of the proton
=
1.67
×
10
–
27
kg
,
charge of the proton
=
1.6
×
10
–
19
C
)
Q.
A beam of protons with a velocity
4
×
10
5
m/s enters a uniform magnetic field of
0.3
tesla at an angle
60
o
to the magnetic field. Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix(which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation).
Q.
A beam of protons with velocity
4
×
10
5
m
/
s
enters a uniform magnetic field of 0.22 T at an angle of
60
o
with magnetic field. Pitch of helical path traced in
c
m
is [Take mass of proton =
1.6
×
10
−
27
k
g
and
π
=
22
7
]
(Write upto two digits after the decimal point.)
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