A beam of protons enters a uniform magnetic field of 0-3 T with a velocity of 4- 105 m-s in a direction making an angle of 60o with the direction of magnetic field- The path of motion of the particle will be -

The correct option is D helical B=0.3T #160; v=4× 10^5 m/sec θ =60^∘ The particle moves in circle due to the component of magnetic field due to ...

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Byju's Answer

Standard XII

Physics

Helical Motion

A beam of pro...

Question

A beam of protons enters a uniform magnetic field of $0.3 T$ with a velocity of $4 \times 10^{5}$ m/s in a direction making an angle of $60^{o}$ with the direction of magnetic field. The path of motion of the particle will be :

circular

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straight line

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parabolic

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helical

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Solution

The correct option is D helical
$B = 0.3 T$
$v = 4 \times 10^{5} m / s e c$
$θ = 60^{\circ}$
The particle moves in circle due to the component of magnetic field due to perpendicular component of magnetic field & due to component parallel to velocity, force on particle =0 it will continue moving in that direction.
It's path will be helical.

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A beam of protons enters a uniform magnetic field of 0.3T with a velocity of 4×105 m/s in a direction making an angle of 60o with the direction of magnetic field. The path of motion of the particle will be :

A beam of protons enters a uniform magnetic field of $0.3 T$ with a velocity of $4 \times 10^{5}$ m/s in a direction making an angle of $60^{o}$ with the direction of magnetic field. The path of motion of the particle will be :