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Question

A beam of rectangular cross-section is subjected to a vertical shear force of 100 kN the shear force carried by middle 13rd portion of the cross section is_____kN.
  1. 48.14

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Solution

The correct option is A 48.14

τ=V(A¯y)Ib

=V2I[(d/2)2y2] (For rectangular)

Shear force in middle third portion

=2d/60τ×bdy

=2d/60V2I[(d/2)2y2]bdy

=VbI[d24yy33]d/60

=VbI[d24×d613(d3216)]

=VbI[271648]d3

=12Vbbd3×26648d3

=1327V

=1327×100 kN

=48.14 kN

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