A- 2 3- 5 7 -B- 0 4- -1 7 -C- 1 0- -1 4 -find AC-B2-10C-

We have A=[ [ 2 amp; 3; 5 amp; 7 ]] B=[ [ 0 amp; 4; 1 amp; 7 ]] C=[ [ 1 amp; 0; 1 amp; 4 ]] #160; AC+ ...

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Transpose of a Matrix

A=[ 2 3; 5 7 ...

Question

$A = [\begin{matrix} 2 & 3 5 & 7 \end{matrix}] B = [\begin{matrix} 0 & 4 - 1 & 7 \end{matrix}] C = [\begin{matrix} 1 & 0 - 1 & 4 \end{matrix}]$
find $A C + B^{2} - 10 C$ .

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A = [\begin{matrix} 2 & 3 5 & 7 \end{matrix}], B = [\begin{matrix} 0 & 4 - 1 & 7 \end{matrix}], C = [\begin{matrix} 1 & 0 - 1 & 4 \end{matrix}]

A C + B^{2} - 10 C

(a + b + c) = 14

(a^{2} + b^{2} + c^{2}) = 74

(a c + b c + c a)

If $A = [\begin{matrix} 2 & - 1 3 & 2 \end{matrix}]$ , $B = [\begin{matrix} 0 & 4 - 1 & 7 \end{matrix}]$ . Find $3 A^{2} - 2 B + 1$ .

[\begin{matrix} 2 & - 1 \\ 3 & 2 \end{matrix}]

[\begin{matrix} 0 & 4 \\ - 1 & 7 \end{matrix}]

\frac{a^{2} - b^{2} - c^{2}}{(a - b) (a - c)} + \frac{b^{2} - c^{2} - a^{2}}{(b - c) (b - a)} + \frac{c^{2} - a^{2} - b^{2}}{(c - a) (c - b)}

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