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Question

A bent wire AB carrying a current I is placed in a region of uniform magnetic field B. The force on the wire AB is


  1. BIL

  2. zero

  3. 32BIL

  4. BIL2


Solution

The correct option is D

BIL2


F=I(l×B)
Here l is directed from end A to end B of the wire.
Here |l|=L2 and θ=90.....F=I×L2×B=BIL2

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