Question

A BG railway track is designed for an equilibrium speed of 80 kmph and maximum speed as 100 kmph. If the radius of the curve is 875 m, then the super elevation to be provided is

• A. 171.50 mm
• B. 150.82 mm
• C. 75.82 mm
• D. 96.5 mm

Answer 1

The correct option is D 96.5 mm

Radius of the curve = 875m

Super elevation for equilibrium speed

$=\frac{G{V}^2}{127R}=\frac{1676\times {80}^2}{127\times 875}=96.52mm$

Suoer elevation for maximum speed
$=\frac{G{V}^2}{127R}=\frac{1676\times {100}^2}{127\times 875}=150.82mm$

Cant deficiency = 150.82 - 96.52 = 54.30mm
Maximum permissible cant deficiency for BG track = 75 mm > 54.03 mm
Hence, Provide super elevation of 96.52 mm