Question

A bicycle chain of length 1.6 m and of mass 1 kg is lying on a horizontal floor. What is the work done in lifting it with one end touching the floor and the other end 1.6 m above the floor?
(take g=$10m{s}^{-2}$)

Answer 1

Given,

Mass of bicycle $m=1Kg$

Length $h=1.6m$

$g=10m/s^2$

So,

Whenever the object is in contact with some other object or walls at the endpoints. its mass is divided into two equal parts.

So work done $W=\frac{mgh}{2}$

Therefore,

$W=\frac{\left(1\right)\left(10\right)\left(1.6\right)}{2}=8J$

Thus, the work is done in lifting it with one end touching the floor and the other end $1.6m$ above the floor is $8J$