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Standard IX

Physics

The Equations of Motion

A bicycle ini...

Question

A bicycle initially moving with a velocity 5.0 m $s^{- 1}$ accelerates for 5 s at a rate of 2 m $s^{- 2}$ . What will be its final velocity?

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Solution

From the first equation of motion, $v = u + a t \Rightarrow v = 5 + 2 \times 5 = 5 + 10 = 15 m / s$

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The Equations of Motion

Standard IX Physics

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A bicycle initially moving with a velocity 5.0 m s−1 accelerates for 5 s at a rate of 2 m s−2. What will be its final velocity?

From the first equation of motion, v=u+at⇒v=5+2×5=5+10=15 m/s

A bicycle initially moving with a velocity 5.0 m $s^{- 1}$ accelerates for 5 s at a rate of 2 m $s^{- 2}$ . What will be its final velocity?

From the first equation of motion, $v = u + a t \Rightarrow v = 5 + 2 \times 5 = 5 + 10 = 15 m / s$