A bicycle initially moving with a velocity $50 m s^{- 1}$ accelerates for $5 s$ at a rate of $2 m s^{- 2}$ . What will be its final velocity?

40 m s^{- 1}

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60 m s^{- 1}

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55 m s^{- 1}

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45 m s^{- 1}

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Solution

The correct option is D $60 m s^{- 1}$
Acceleration, $a = \frac{v_{f} - v_{i}}{t}$
Therefore, $2 m / s^{2} = \frac{v_{f} - 50 m / s}{5 s}$
$v_{f} = 60 m / s$

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A bicycle initially moving with a velocity 50ms−1 accelerates for 5 s at a rate of 2ms−2. What will be its final velocity?

The correct option is D 60ms−1Acceleration, a=vf−vitTherefore, 2m/s2=vf−50m/s5svf=60m/s

A bicycle initially moving with a velocity $50 m s^{- 1}$ accelerates for $5 s$ at a rate of $2 m s^{- 2}$ . What will be its final velocity?

The correct option is D $60 m s^{- 1}$
Acceleration, $a = \frac{v_{f} - v_{i}}{t}$
Therefore, $2 m / s^{2} = \frac{v_{f} - 50 m / s}{5 s}$
$v_{f} = 60 m / s$