A bicyclist comes to a skidding stop in $10 m$ . During this process, the force on the bicycle due to the road is $200 N$ and is directly opposed to the motion. The work done by the cycle on the road is:

+ 2000 J

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- 200 J

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Zero

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- 20000 J

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Solution

The correct option is C Zero
Given,
$F = - 200 N$
$x = 10 m$
As the road does not move so, $d i s p l a c e m e n t = 0$
The work done by the cycle on the road is
$W = f o r c e \times d i s p l a c e m e n t$
$W = 200 \times 0 = 0 J$
The correct option is C.

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