A bike is moving with speed 54 kg/h. When the biker applies force on the brakes, it takes 5 seconds for the bike to come to rest. If the mass is 200kg, find the force applied on brakes.

Open in App

Solution

Dear Student

u = 54 km/h = 15 m/s
v = 0
t = 5 s
we know that, v = u + at
0 = 15 + a × 5
0 = 15 + 5a
5a = - 15
a = - 15/5 = - 3 m/s²

Retardation = 3 m/s²

F = ma
F = 200 × 3
F = 600 N

Regards

Suggest Corrections

Similar questions

Q. A car of mass 1000 kg moving with a velocity of 20 m/s is brought to rest by applying brakes in 10 seconds. What is the force applied by the brakes?

A motor bike running at 90km/h is slowed to 54km/h by the application of brakes over a distance of 40 m if the brakes are applied with the same force calculate the :

1 total time in which bike comes to rest

2 total distance travelled by the bike

a car is moving with a velocity of 180 kmph antiques 6 seconds to stop after the brakes are applied .calculate the force exerted by the brakes if mass is 500 kgs

What force must the brakes apply to a truck of mass 2800 kg moving with a speed of 3 metre per second to bring it to rest in 8 seconds

Q. A track of mass 1800 kg moving with a speed of 54 kg per hour.when brakes are applied it stops with uniform negative acceleration at a distance of 200 m. calculate the force applied by the brakes of the truck and the work done before stopping.

Join BYJU'S Learning Program

A bike is moving with speed 54 kg/h. When the biker applies force on the brakes, it takes 5 seconds for the bike to come to rest. If the mass is 200kg, find the force applied on brakes.

Dear Student u = 54 km/h = 15 m/s v = 0 t = 5 s we know that, v = u + at 0 = 15 + a × 5 0 = 15 + 5a 5a = - 15 a = - 15/5 = - 3 m/s2 Retardation = 3 m/s2 F = ma F = 200 × 3 F = 600 N Regards

Dear Student

u = 54 km/h = 15 m/s
v = 0
t = 5 s
we know that, v = u + at
0 = 15 + a × 5
0 = 15 + 5a
5a = - 15
a = - 15/5 = - 3 m/s²

Retardation = 3 m/s²

F = ma
F = 200 × 3
F = 600 N

Regards