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Question
A bimetallic strip of brass and steel, each having thickness of 1 cm, is kept at 20oC. The strip bends with brass on outer side. The radius of curvature of curved surface is : (αbrass=18×10−6 /oC,αsteel=12×10−6 /oC)
A bimetallic strip of brass and steel, each having thickness of 1 cm, is kept at 20oC. The strip bends with brass on outer side. The radius of curvature of curved surface is : (αbrass=18×10−6 /oC,αsteel=12×10−6 /oC)
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Solution
The correct option is A 16.67 m
radius = r=d(α1−α2)△twhere d = thickness = 1 cm=1×10−2m
α1=αbrass=18×10−6/oCα2=αsteel=12×10−6/oCAssuming change in temperature = △t=100oCr=1×10−2(6×10−6)100r=16.67m
radius = r=d(α1−α2)△t
where d = thickness = 1 cm=1×10−2m
α1=αbrass=18×10−6/oC
α2=αsteel=12×10−6/oC
Assuming change in temperature = △t=100oC
r=1×10−2(6×10−6)100r=16.67m
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