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Atomic Number and Mass Number

A binary comp...

Question

A binary compound between an unknown element $E$ and hydrogen contains $91.27$ % $E$ and $8.73$ % $H$ by mass. If the formula of the compound is $E_{3} H_{8}$ . Calculate the atomic mass of $E$ .

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Solution

Given formula of the compound $E_{3} H_{8}$
Moles of E present in the compound is 3
$N o . o f m o l e s = \frac{G i v e n m a s s}{M o l a r m a s s o f t h e c o m p o u n d}$
$3 = \frac{91.27}{M o l a r m a s s o f t h e c o m p o u n d}$
Molar mass of the compound=30
$3 \times E + 8 \times 1 = 30 E = 7.3$
Atomic mass of E is 7.3

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