A binary solid $(A^{+} B^{-})$ has a zinc blende structure with $B^{-}$ ions constituting the lattice and $A^{+}$ ions occupying $25 %$ tetrahedral holes. The formula of solid is:

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A_{2} B

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A B_{2}

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A B_{4}

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Solution

The correct option is B $A B_{2}$
Let the number of unit cells $= n$
Then, number of tetrahedral voids $2 n$
25% of tetrahedral voids $= \frac{25}{100} \times 2 n = \frac{n}{2}$
So, the required formula is $A_{n / 2} B_{n} o r A B_{2}$

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A binary solid (A+B−) has a zinc blende structure with B− ions constituting the lattice and A+ ions occupying 25% tetrahedral holes. The formula of solid is:

The correct option is B AB2Let the number of unit cells =nThen, number of tetrahedral voids 2n25% of tetrahedral voids =25100×2n=n2So, the required formula is An/2Bn or AB2

A binary solid $(A^{+} B^{-})$ has a zinc blende structure with $B^{-}$ ions constituting the lattice and $A^{+}$ ions occupying $25 %$ tetrahedral holes. The formula of solid is:

The correct option is B $A B_{2}$
Let the number of unit cells $= n$
Then, number of tetrahedral voids $2 n$
25% of tetrahedral voids $= \frac{25}{100} \times 2 n = \frac{n}{2}$
So, the required formula is $A_{n / 2} B_{n} o r A B_{2}$