A binary solid (AB) has NaCl type of structure,if all ions are removed from one of the body diagonal planes, then new formula becomes:

A_{3} B_{4}

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A B

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A_{4} B_{3}

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A_{2} B_{3}

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Solution

The correct option is A $A B$
Removal of all atoms along body diagonal plane means removal of: 4 corners, 1 body centre, 2 edge centres and 2 face centres.
Hence $1 N a^{+}$ ions will be removed from body centre and 2 from edge centres.
$C l^{-}$ ions will beremoved from corners and 2 from face centres.
On calculating contribution of all ions $\frac{5}{2}$ ions of $N a^{+}$ and $\frac{5}{2}$ ions of $C l^{-}$ are found to be there.
Ratio is $1 : 1$
So formula will be $A B$

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