Question

A bird flies at a angle ${60}^0$ to the horizontal. its horizontal component of velocity is$10m{s}^{-1}$, find the vertical component of velocity

• A. $10\sqrt{3}$
• B. $10\sqrt{4}$
• C. $5$
• D. $26$

Answer 1

The correct option is A $10\sqrt{3}$

Lets consider, $u=$ initial velocity of the particle

Given,

$\theta ={60}^0$

Horizontal component of velocity, $u_x=ucos\theta =10m/s$

$ucos{60}^0=10$

$u=\frac{10}{cos{60}^0}=\frac{10}{0.5}$

$u=20m/s$

Vertical component of velocity, $u_y=usin\theta$

$u_y=20\times sin{60}^0=20\times \frac{\sqrt{3}}{2}$

$u_y=10\sqrt{3}m/s$

The correct option is A.