Question

A bird in air looks at a fish directly below it, inside a transparent liquid in a container. If distance of bird as estimated by the fish is $h_2$ and the distance of fish as estimated by bird is $h_1$, then refractive index of the liquid is

• A. $\frac{h_1}{h_2}$
• B. $\frac{h_2}{h_1}$
• C. $\frac{h_2+h_1}{h_1-h_2}$
• D. $\frac{h_1-h_2}{h_1+h_2}$

Answer 1

The correct option is A $\frac{h_1}{h_2}$

The refractive index of the medium 2 wrt medium 1 is given by, the relative distance estimated by the bodies in the two mediums for each other.
Thus, as given in the question, if n be the refractive index,
then it will be equal to, $n=\frac{h_1}{h_2}$