A bird is flying $12 m$ above the surface of a pond. What is the apparent position of the bird as viewed by a fish $1 m$ below the surface? ( $_{a} μ_{w} = \frac{4}{3}$ )

16 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

17 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

15 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

13 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $17 m$
$h = 12 m, h^{'} = ?$

$_{a} μ_{w} = \frac{4}{3}, d = 1 m$

$_{a} μ_{w} = \frac{h^{'}}{h_{1}} : \frac{4}{3} = \frac{h}{12}$

$h^{'} = \frac{4}{3} \times 12 = 16 m$

Total height $= h^{'} + d = (16 + 1) m = 17 m$

Suggest Corrections

Similar questions

Q. A bird is flying 12 m above the surface of a pond. what is the apparent position of the bird as viewed by a fish 1 m below the surface?

(_{a} μ_{w} = \frac{4}{3})

A bird is flying 12m above the surface of a pond. The apperant position of the bird as viewed by a fish 1m below the surface is ? n of water = 1.33

Q. A bird is flying 12 m above the surface of pond. The apparent position of the bird as viewed by a fish 1 m below the surface is:

(μ_{w} = \frac{4}{3})

A bird flying above a pond starts moving vertically down towards the water below at a speed of v m/s. Find its apparent velocity as viewed by a fish located at a depth of d m below the surface of water.

Q. A bird is flying

3 m

above the surface of water. If the bird is diving vertically down with speed of

6 m / s

, its apparent velocity as seen by a stationary fish underwater is :

(μ_{w a t e r} = \frac{4}{3})

Join BYJU'S Learning Program

A bird is flying 12m above the surface of a pond. What is the apparent position of the bird as viewed by a fish 1m below the surface? (aμw=43)

The correct option is B 17mh=12 m,h′=? aμw=43,d=1m aμw=h′h1:43=h12h′=43×12=16m Total height =h′+d=(16+1)m=17m

A bird is flying $12 m$ above the surface of a pond. What is the apparent position of the bird as viewed by a fish $1 m$ below the surface? ( $_{a} μ_{w} = \frac{4}{3}$ )

The correct option is B $17 m$
$h = 12 m, h^{'} = ?$

$_{a} μ_{w} = \frac{4}{3}, d = 1 m$

$_{a} μ_{w} = \frac{h^{'}}{h_{1}} : \frac{4}{3} = \frac{h}{12}$

$h^{'} = \frac{4}{3} \times 12 = 16 m$

Total height $= h^{'} + d = (16 + 1) m = 17 m$