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Question

A bird is flying 3 m above the surface of water of refractive index 4/3 If the bird is diving vertically down with speed 6 m/s, his apparent velocity as seen by a stationary fish underwater (in m/s) is:

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Solution

Given
Distance of bird from surface h=3 m
Refractive index of water μwater=4/3
Velocity of the bird dhdt=6 m/s

μairh=μwaterhi
1h=μwaterhi

Apparent height of bird fom surface
hi= μwater(h)

Apparent velocity of bird as observed by fish = dhidt=μwaterdhdt=43×6=8 m/s

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