Question

A bird is flying at a height of 30 m above the ground. The angle of elevation of the bird from an observer is ${30}^{\circ }$. Find the distance(in meters), between the observer and the bird.

• A. 60
• B. 40
• C. 30
• D. 20√3

Answer 1

The correct option is A

60

$\text{The given situation can be represented by the figure below.}$

$\text{In the given right-angled triangle,}$
$sin{30}^{\circ }=\frac{AB}{AC}\Rightarrow AC=\frac{AB}{sin{30}^{\circ }}=\frac{30}{\frac{1}{2}}=60m$
$\therefore Thedistancebetweenthebirdandtheobserveris60m.$