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Question

A bird is flying towards north with a velocity 40 km/h and a train is moving with a velocity 40 km/h towards east. What is the velocity of the bird noted by a man in the train?

A
402 km/h NE
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B
402 km/h SE
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C
402 km/h NW
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D
402 km/h SW
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Solution

The correct option is C 402 km/h NW
Relative velocity of bird with respect to train, VB/T=VBVT
where VB and VT are the velocity of bird and train with respect to ground.
Since VB=40 km/h due north
VT=40 km/h due east
VT=40 km/h due west
Thus magnitude of relative velocity, VB/T=(40)2+(40)2=402 km/h

Since VB is in north direction and VT will be in west direction, hence there resultant should be in north-west direction.

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