wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bird is sitting on train A moving towards East with a velocity 300 km/hr. Another train B of same speed is moving in West direction on the same track. When the trains are 6 km apart, the bird starts flying with a velocity 30 km/hr with respect to ground towards B. After touching B, it returns back to A and continue repeating this process until the trains collide. In this process, the total distance traveled by the bird is:

318917_0cc3d7af949741b684ff7153bb973d7c.png

A
100 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
200 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
300 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
6 km
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 300 m
Relative velocity between trains: 600mkh1
Time taken for crash is:
t=dv=6600=1100hours=36s
Velocity of bird =30kmh1=30518ms1
Distance traveled by bird is =3051836=300m
Hence option C is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon