Question

# A Bird Shooter Was Asked How Many Birds He Had In The Bag. He Replied That There Were All Sparrows But Six, All Pigeons But Six, And All Ducks But Six. How Many Birds He Had In The Bag In All?

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Solution

## Let the total number of birds in the bag will be $x$As given in the question: $Numberofsparrows=x-6\phantom{\rule{0ex}{0ex}}Numberofpigeons=x-6\phantom{\rule{0ex}{0ex}}Numberofducks=x-6$Therefore, $Thetotalnumberofbirds=Numberofsparrows+Numberofpigeons+Numberofducks$$x=\left(x-6\right)+\left(x-6\right)+\left(x-6\right)\phantom{\rule{0ex}{0ex}}x=3x-18\phantom{\rule{0ex}{0ex}}$ (By removing bracket)$x-3x=-18$ (By transposing $3x$ from R.H.S to L.H.S) $-2x=-18$ (Cancel $\left(-\right)$ sign both sides)$2x=18\phantom{\rule{0ex}{0ex}}x=9$Hence the total number of birds in the bags will be $9$.

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