A biscuit factory produced $950$ biscuit packets in a day. How many biscuit packets will the factory produce in the three months Jan, Feb, and March (There are no holidays during these months)

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Solution

$950$ packets for day

No. of packets in 3 months $\Rightarrow$

$= 950 \times (31 + 28 + 31)$

$= 950 \times 90$

$= 85500$ packets.

(NOTE $\to$ year is not a leap year..)

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A biscuit factory produced 950 biscuit packets in a day. How many biscuit packets will the factory produce in the three months Jan, Feb, and March (There are no holidays during these months)

950 packets for dayNo. of packets in 3 months ⇒=950×(31+28+31)=950×90=85500 packets.(NOTE → year is not a leap year..)

A biscuit factory produced $950$ biscuit packets in a day. How many biscuit packets will the factory produce in the three months Jan, Feb, and March (There are no holidays during these months)

$950$ packets for day

No. of packets in 3 months $\Rightarrow$

$= 950 \times (31 + 28 + 31)$

$= 950 \times 90$

$= 85500$ packets.

(NOTE $\to$ year is not a leap year..)