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Question

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is (in amu):

A
182
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B
168
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C
192
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D
188
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Solution

The correct option is D 188
Atomic mass of metal =32×2=64 amu
Molar mass of metal nitrate =M(NO3)2
= 64 + 28 + 48 + 48 = 188.

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