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Standard VI

Chemistry

Physical and Chemical Changes

A black body ...

Question

A black body at a temperature of $227^{o} C$ radiates heat energy at the rate 5 cal/cm $^{2} - s$ . At a temperature of $727^{o} C$ , the rate of heat radiated per unit area in cal/cm $^{2}$ will be

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160

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250

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500

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Solution

The correct option is A 80
According to Stefen's Law, the rate of heat radiation from body is proportional to the fourth power of body's temperature.
Thus $P \propto T^{4}$
$⟹ \frac{P_{2}}{P_{1}} = \frac{T_{2}^{4}}{T_{1}^{4}}$
$= 16$
$⟹ P_{2} = 80 c a l / c m^{2} - s$

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Similar questions

Q. A black body at a temperature of

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5 c a l / c m^{2} / s

. At a temperature of

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A black body at a temperature of 227oC radiates heat energy at the rate 5 cal/cm2−s. At a temperature of 727oC, the rate of heat radiated per unit area in cal/cm2 will be

The correct option is A 80According to Stefen's Law, the rate of heat radiation from body is proportional to the fourth power of body's temperature.Thus P∝T4⟹P2P1=T42T41=16⟹P2=80cal/cm2−s

A black body at a temperature of $227^{o} C$ radiates heat energy at the rate 5 cal/cm $^{2} - s$ . At a temperature of $727^{o} C$ , the rate of heat radiated per unit area in cal/cm $^{2}$ will be

The correct option is A 80
According to Stefen's Law, the rate of heat radiation from body is proportional to the fourth power of body's temperature.
Thus $P \propto T^{4}$
$⟹ \frac{P_{2}}{P_{1}} = \frac{T_{2}^{4}}{T_{1}^{4}}$
$= 16$
$⟹ P_{2} = 80 c a l / c m^{2} - s$