A black body at a temperature of 327∘C radiates 4cal cm−2s−1 at a temperature of 927∘C, the rate of heat radiated per unit area in cal cm−2s−1 will be
A
16
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B
32
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C
64
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D
128
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Solution
The correct option is C64 Here, T1=327∘C=(327+273)K=600K and T2=927∘C=(927+273)K=1200K According to Stefan's law E∝T4 E2E1=(T2T1)4=(1200600)4=16 E2=16E1=16×4=64cal cm−2s−1