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Question

A black body is at a temperature of 2880 K. The

energy of radiation emitted by this object with

wavelength between 499 nm and 500 nm is U1,

between 999 nm and 1000 nm is U2 and between

1499 nm and 1500 nm is U3. The Wein's constant

b = 2.88 x 106 nm K. Then


A

U1=0

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B

U3=0

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C

U1>U2

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D

U2>U1

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Solution

The correct option is D

U2>U1


Wein's displacement law is λmT=b

λm = bT = 2.88 × 1062880 = 1000 nm.

Energy distribution with wavelength will be as follows

From the graph it is clear that U2 > U1.


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