A black body is at a temperature of 2880 K. The energy of radiation emitted by this body between wave lengths 499 nm and 500 nm is $U_{1}$ , between 999 nm and 1000 nm is $U_{2}$ and between 1499 nm and 1500 nm is $U_{3}$ . The Wien’s constant b = 2.88 $\times$ 106 nm K. Then

A black body is at a temperature of 2880 K. The

energy of radiation emitted by this object with

wavelength between 499 nm and 500 nm is $U_{1}$ ,

between 999 nm and 1000 nm is $U_{2}$ and between

1499 nm and 1500 nm is $U_{3}$ . The Wein's constant

b = 2.88 x $10^{6}$ nm K. Then

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A black body is at a temperature of 2880 K. The energy of radiation emitted by this body between wavelengths 499 nm and 500 nm is U1; between 999 nm and 1000 nm is U2; and between 1499 nm and 1500 nm is U3. Then, (Wein's constant b=2.88×106nmK)

The correct option is A U2>U1According to wein's displacement law we know that λmaxT=constantSo, λmaxT=b----(suppose)So, λmax=bT=2.88×106nmK2880K=1000nmHence, U2 is maximum since all the wavelength ranging from zero to infinity,so U1 and U2 are not zero.

A black body is at a temperature of $2880$ K. The energy of radiation emitted by this body between wavelengths $499$ nm and $500$ nm is $U_{1}$ ; between $999$ nm and $1000$ nm is $U_{2}$ ; and between $1499$ nm and $1500$ nm is $U_{3}$ . Then, (Wein's constant $b = 2.88 \times 10^{6} n m K$ )