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Question

A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm, is U2 and between 1499 nm and 1500 nm is U3. Wien's constant, b=2.88×106nmK. Then

A
U1=0
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B
U3=0
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C
U1=U2
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D
U2>U1
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Solution

The correct option is D U2>U1
Wien's displacement law is
λmT=b(b=Wiens constant)
λm=bT=2.88×106nmK2880 K
λ=1000 nm
Energy distribution with wavelength will be as follows:
From the graph it is clear that
U2>U1 (in fact U2 is maximum).
935973_1016000_ans_9600411b473946209d34c3e8888019cc.png

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