A black metal foil is warmed by radiation from a small sphere at temperature ‘T′ and at a distance ‘d′. It is found that the power received by the foil is P. If both the temperature and distance are doubled, the power received by the foil will be :
A
16P
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B
4P
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C
2P
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D
P
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Solution
The correct option is B4P Emissive power of a body is given as : E=σT4 E∝1r2 T41r21=T42r22 T41r21=P⇒(2T1)4(2r1)2=4P