wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A black mineral (A) is soluble in NaCl solution forming (B). On adding Zn into (B), metal (C) is formed. Metal (C) on boiling with HNO3 forms (D) which gives white ppt (E) with NaCl soluble in NH3 solution. (A) can be obtained when (D) reacts with hypo. (A) to (E) are
(A) : Ag2S
(B) : Na[Ag(CN)2]
(C) : Ag
(D) : AgNO3
(E) : AgCl .
If true enter 1, else enter 0.

Open in App
Solution

A black mineral Ag2S is soluble in NaCN solution forming Na[Ag(CN)2].

Ag2S+4NaCNNa2S+2Na[Ag(CN)2]

On adding Zn into Na[Ag(CN)2], Ag metal is formed.

Zn+2Na[Ag(CN)2]Na2[Zn(CN)4]+2Ag

Ag metal on boiling with HNO3 forms AgNO3

2Ag+2HNO32AgNO3+H2

AgNO3 gives white ppt AgCl with NaCl soluble in NH3 solution.

AgNO3+NaClAgCl(white)+NaNO3

AgCl+2NH3[Ag(NH3)2]Cl

Ag2S can be obtained when AgNO3 reacts with hypo.

Na2S2O3+2AgNO3Ag2S2O3whitewater−−Ag2Sblack+H2SO4

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Interstitial Compounds
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon