Question

A block A has a velocity of $0.6m/s$ to the right, determine the velocity of cylinder $B$.

• A. $1.2m/s$
• B. $2.4m/s$
• C. $1.8m/s$
• D. $3.6m/s$

Answer 1

Answer: (C)

$1.8m/s$

Given,

$V_A=0.6m/s$

If block B will move downward by displacement $x$ than block A will move by displacement of $3x$

Now we can write

$x_B=3x_A$

Differentiate both side with respect to $t$

$\frac{d{x}_B}{dt}=3\frac{d{x}_A}{dt}{V}_B=3V_A$

Putting the value of velocity of block A in above equation

$V_B=3\times 0.6=1.8m/s$

Correct option is C.