A block $A$ of mass $2 k g$ rests on a horizontal surface. Another block $B$ of mass $1 k g$ moving at a speed of $1 m / s$ when at a distance of $16 c m$ from $A$ , collides elastically with $A$ . The coefficient of friction between the horizontal surface and each of the blocks is $0.2$ . Then, $(g = 10 m / s^{2})$

after collision block

B

rebounds

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after collision block

B

comes to rest

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final separation between the blocks is

3 c m

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final separation between the blocks is

5 c m

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Solution

The correct options are
A after collision block $B$ rebounds
D final separation between the blocks is $5 c m$

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Similar questions

Q. A small block of mass

M

moves with velocity

5 m s^{- 1}

towards an another block of same mass

M

placed at a distance of

2 m

on a rough horizontal surface. Coefficient of friction between the blocks and ground is

0.25

. Collision between the two blocks is elastic, the separation between the blocks, when both of them come to rest, is (

g = 10 m s^{- 2}

)

The friction coefficient between the horizontal surface and each of the blocks shown in figure is 0.20. The collision between the blocks is perfectly elastic. Find the separation between the two blocks when they come to rest. Take $g$ = 10 $m / s^{2}$ .