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Finding Friction's Direction

A block A of ...

Question

A block A of mass 5 Kg is placed on a rough table. The coefficient of static & kinetic friction between surfaces of block and table be 0.4 & 0.3 respectively. If the force F exerted on the block is 10 N (g = 10 m/s²) the force of friction between block and table is.

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Solution

Given:- mass=5 kg
Coefficient of static friction=μ_s₌0.4
Then limiting force of friction= f_s=μ_sR
=μ_smg
=0.4 X 5 X 9.8
=19.6 N
Since:-F=10 N
As applied force F < f_s, therefore,block does not move further, as static friction is self adjusting.

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