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Question

A block A, whose weight is 200 N, is pulled up a slope of length 5 m by means of a constant force F(=150 N) as illustrated in the figure.The difference in work done by the force and the increase in potential energy of the block is :

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A
0J
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B
150J
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C
750J
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D
600J
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Solution

The correct option is B 150J
W=F×s
Here angle between force and displacement is 0 degree.Force applied due to weight of body is zero as in this case gravitational force and displacement are perpendicular.
F=150N;S=5 m.
W=150×5=750J
P.E=m×g×h
m×g=200N;h=3 m because one of the perpendicular side has length of 3 m
P.E=200×3=600J
Hence difference is 750600=150J.

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