A block A, whose weight is 200N, is pulled up a slope of length 5m by means of a constant force F(=150N) as illustrated in the figure.The difference in work done by the force and the increase in potential energy of the block is :
A
0J
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B
150J
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C
750J
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D
600J
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Solution
The correct option is B150J W=F×s Here angle between force and displacement is 0 degree.Force applied due to weight of body is zero as in this case gravitational force and displacement are perpendicular. F=150N;S=5m. W=150×5=750J P.E=m×g×h m×g=200N;h=3m because one of the perpendicular side has length of 3 m P.E=200×3=600J Hence difference is 750−600=150J.