wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A block A, whose weight is 200 N, is pulled up a slope of length 5 m by means of a constant force F(=150 N) as illustrated in the figure.The difference in work done by the force and the increase in potential energy of the block is :

185941.jpg

A
0J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
750J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
600J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 150J
W=F×s
Here angle between force and displacement is 0 degree.Force applied due to weight of body is zero as in this case gravitational force and displacement are perpendicular.
F=150N;S=5 m.
W=150×5=750J
P.E=m×g×h
m×g=200N;h=3 m because one of the perpendicular side has length of 3 m
P.E=200×3=600J
Hence difference is 750600=150J.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
So You Think You Know Work?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon