A block and tackle system has the velocity ratio $3$ . A man can exert a pull of $200 k g f$ . What is the maximum load he can raise with this pulley system if its efficiency is $60 %$

250 k g f

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260 k g f

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350 k g f

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360 k g f

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Solution

The correct option is C $360 k g f$
$M e c h a n i c a l a d v a n t a g e = V e l o c i t y R a t i o \times E f f i c i e n c y$
$M . A = 3 \times \frac{60}{100} = 1.8$
$M . A = \frac{l o a d}{e f f o r t}$
$∴ l o a d = M . A \times e f f o r t$
$\Rightarrow 1.8 \times 200 = 360 k g f$

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Similar questions

A block and tackle system has the velocity ratio 3. Draw a labelled diagram of the system indicating the points of application and the directions of load L and effort E. A man can exert a pull of 200 kgf. (a) What is the maximum load he can raise with this pulley system if its efficiency is $60 %$ ? (b) If the effort end moves a distance 60 cm, what distance does the load move ?

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A block and tackle system has the velocity ratio 3. A man can exert a pull of 200kgf. What is the maximum load he can raise with this pulley system if its efficiency is 60%

The correct option is C 360kgfMechanicaladvantage=VelocityRatio×EfficiencyM.A=3×60100=1.8M.A=loadeffort∴load=M.A×effort⇒1.8×200=360kgf

A block and tackle system has the velocity ratio $3$ . A man can exert a pull of $200 k g f$ . What is the maximum load he can raise with this pulley system if its efficiency is $60 %$

The correct option is C $360 k g f$
$M e c h a n i c a l a d v a n t a g e = V e l o c i t y R a t i o \times E f f i c i e n c y$
$M . A = 3 \times \frac{60}{100} = 1.8$
$M . A = \frac{l o a d}{e f f o r t}$
$∴ l o a d = M . A \times e f f o r t$
$\Rightarrow 1.8 \times 200 = 360 k g f$