A block and tackle system have the velocity ratio 3. A man can exert a pull of 200 kgf. What is the maximum load he can raise with this pulley system if its efficiency is 50%?

300 kgf

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360 kgf

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600 kgf

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180 kgf

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Solution

The correct option is A
300 kgf

Given, velocity ratio = 3
Effort = 200 kgf
Efficiency ( $η$ ) = 50%

We know that when efficiency is 100% then,
Effort (E) = $\frac{Load}{n (number of pulleys)}$
$\Rightarrow 200 = \frac{L}{3}$

$\Rightarrow L = 600 k g f$

When, efficiency is given as 50%.

So, Maximum load that can be raised

= $\frac{50}{100} \times 600 = 300 k g f$

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A block and tackle system have the velocity ratio 3. A man can exert a pull of 200 kgf. What is the maximum load he can raise with this pulley system if its efficiency is 50%?

The correct option is A 300 kgf Given, velocity ratio = 3 Effort = 200 kgf Efficiency (η) = 50% We know that when efficiency is 100% then, Effort (E) = Loadn (number of pulleys) ⇒200=L3 ⇒L=600 kgf When, efficiency is given as 50%. So, Maximum load that can be raised = 50100×600=300 kgf