A block and tackle system of 5 pulleys consist of 3 pulleys in the upper block and 2 pulleys in the lower block. If the load is raised by 1 m, through what distance will effort move?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
5m

As there are 5 strings in the block and tackle system,

Velocity ratio of the system = V.R = n = 5

Also $d_{L}$ = 1m

V.R = $\frac{d_{E}}{d_{L}}$ or $d_{E}$ = 5 $\times$ $d_{L}$ = 5 $\times$ 1 = 5m

Suggest Corrections

Similar questions

An ideal block and tackle system of 5 pulleys consist of 3 pulleys in the upper block and 2 pulleys in the lower block. If the load is raised by 1 m, through what distance will effort move.

The given figure shows a block and tackle system of pulleys used to lift a load. When the load is pulled up by a distance 1 m, how far does the effort end move?

Q. In a block and tackle system consisting of

3

pulleys, a load of

75 k g f

is raised with an effort of

25 k g f

Find the efficiency?

In a block and tackle system consisting of

3

pulleys, a load of

75 k g f

is raised with an effort of

25 k g f

Find the mechanical advantage.

The given figure shows a block and tackle system of pulleys used to lift a load. When the load pulled up by a distance 1m, how much do the effort end move?

Join BYJU'S Learning Program

A block and tackle system of 5 pulleys consist of 3 pulleys in the upper block and 2 pulleys in the lower block. If the load is raised by 1 m, through what distance will effort move?

The correct option is C 5m As there are 5 strings in the block and tackle system, Velocity ratio of the system = V.R = n = 5 Also dL​ = 1m V.R = dEdL or dE​ = 5 × dL​ = 5 × 1 = 5m

The correct option is C
5m

As there are 5 strings in the block and tackle system,

Velocity ratio of the system = V.R = n = 5

Also $d_{L}$ = 1m

V.R = $\frac{d_{E}}{d_{L}}$ or $d_{E}$ = 5 $\times$ $d_{L}$ = 5 $\times$ 1 = 5m