A block and tackle system of 5 pulleys is used to raise a load of 50 kgf steadily through a height of 20 m. The work done against friction is 2000J. Calculate the work done by the effort
The correct option is:D:12000 J
Given Data:
Number of pully, =5
Load of one object, =50kgf=50×10=500N
Hight of lifting the load, =20m
Work done to lift the load, 500N×20m=10000J
Work done against friction, Wf=2000J
Total work done, =Wf+WL=2000+10000=12000J