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Work Done by Force of Gravity

A block and t...

Question

A block and tackle system of 5 pulleys is used to raise a load of 50 kgf steadily through a height of 20 m. The work done against friction is 2000J. Calculate the work done by the effort

A

12000 J

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B

16000 J

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C

20000 J

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D

8000 J

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Solution

The correct option is:D:12000 J
Given Data:
Number of pully, $= 5$
Load of one object, $= 50 k g f = 50 \times 10 = 500 N$
Hight of lifting the load, $= 20 m$
Work done to lift the load, $500 N \times 20 m = 10000 J$
Work done against friction, $W_{f} = 2000 J$
Total work done, $= W_{f} + W_{L} = 2000 + 10000 = 12000 J$

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