A block at rest explodes into three equal parts. Two parts starts moving of along x and y axis respectively with equal speed of 10m/s. Find the initial velocity of the third part.
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Solution
The block exploded due to its internal energy so , the net external force during this process is 0 .
Therefore , centre of mass will not change .
Let the body when exploded was at origin of co-ordinate system.
If the two parts of body having equal masses moving at a speed of 10m/s in positive x-axis and positive y-axis direction respectively then, third particle velocity :
V=√(102+102+2×10×10cos90o)=10√2m/s45o with respect to positive x-axis
And if the centre of mass is at rest then the third part of the body which have equal mass with other two , will move in opposite direction (which is 135o with respect to x-axis) of the resultant at the same velocity.