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Question

# A block B of mass 2 kg rests on a rough inclined plane making an angle of 30o with the horizontal surface. The coefficient of static friction between the block and the plane is 0.7. The friction force on the block is:

A
9.8 N
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B
0.7×9.83N
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C
9.8×7 N
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D
0.8×9.8 N
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Solution

## The correct option is B 0.7×9.8√3NGiven that, Mass m=2 kg Angle α=300 Friction coefficient μ=0.7 Now, according to diagramNormal force N=mgcosαFriction=μN Now, the friction force Ff=μN Ff=0.7×2×9.8×√32 Ff=0.7×9.8×√3 NHence, the friction force is 0.7×9.8×√3 N

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